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Question

A computer system has a 36-bit virtual address space with a page size of 8K, and 4 bytes per page table entry. What is the maximum size of addressable physical memory in this system?

Comments

how did you calc 32 TB??

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yes, 2⁴⁵B = 32TB

see, 4Bytes = 32bits, now you will get maximum MM size when these all bits(32) are used to denote frames, now,

for frame----> 32 bits

for offset----> 13 bits

total bits for physical addr = 32 + 13 = 45 bits

total MM size = 2⁴⁵bytes = 32TB

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@joshi_nitish Sir when virtual address space is 36 bits we can address up to 2^36 bytes only then how will address this 2^45 bytes of physical memory. 

I am not able to visualize this solution. Can you help me with an example to understand this problem?