Recent questions tagged paging

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A computer system has a 36-bit virtual address space with a page size of 8K, and 4 bytes per page table entry.What is the maximum size of ... system?doubt- How to determine physical memory when only logical address space is given?
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In a 32-bit machine we subdivide the virtual address into 4 segments as follows: 10-bit8-bit6-bit8 bitWe use a 3-level page table, such that the ... address 0?How to solve such questions?? please someone answer it with proper explanation
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When the valid – invalid bit is set to valid, it means that the associated page :a) is in the TLBb) has data in itc) is in the process’s logical address spaced) is the system’s physical address space
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A certain computer provides its users with a virtual address of $20$ bits, the physical address of $32$ bits. The system uses demand paged environment with page size is ... starting from $10$ to $30$ frames and frame index start with $0$.
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Consider the following memory organization of a processor. The virtual address is 40 bits, the physical address is 32 bits, the page size is 8 KB. The processor has a 4 ... 64 bytes.What is the total size of the page table? 8MB 10MB 2MB
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Main memory is partition into Chunks inI. Simple Paging.II. Virtual memory PagingIII. Simple segmentation.IV. Virtual memory segmentationa) I & II b) I & ... II and III d) AllAns::(a) is it Correct..?
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Answer given is B, but I think it should be D. Stack will pop the least recently used page from the top. How can having most recently used page on top help in LRU implementation?
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Should we have to change the mode while modifying the page table?
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In a two level paging environment a page table is divided into 2^12 pages each of size 4 KW. The memory is word addressable, The physical address space is ... is divided into 2^14 frames. Length of the logical address is(in bits) __________
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If the total number of available frames is 50, and there are 2 processes one of 10 pages and the other of 5 pages then how much of memory ... and 10 respectivelySource: http://nptel.ac.in/courses/106108101/pdf/Worked_Out_Problems/Mod_4.pdf
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Consider a Memory Management System where TLB hit rate is 90% whose access time is 1 cycle. The hit ratio for cache is 80% and if access time is 1 ... time when the cache is virtually addressed is __________ cycle. (Upto 2 decimal places)
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An operating system supports a paged virtual memory, using a central processor with a cycle time of one microsecond. It costs an additional one ... drum transfers ?$30$ microseconds$34$ microseconds$60$ microseconds$68$ microseconds
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Q.Suppose you have a computer system with a 48-bit logical address, page size of 16KB and 4 bytes per page table entry. If we have a 48MB program such that ... in a single page.How much memory is used by program, including its page tables?
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Account for the validity and justification about the correctness of this statement" Whatever level page table is always the nuber of bits which are going to refer a frame number will always going to be same "
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Suppose you have a computer system with a 48-bit logical address, page size of 16K and 4 bytes per page table entry. If we have a 48MB program such that the entire program ... its page tables? 216(3111) 216(3121) 28(3121) 210(3121)
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Consider a system using multi level paging environment. Address bits are segregated as follows: Here first 8 bits represent the required bits for first level, next 8 bits ... each page table entry is 4 bytes. 2048 3192 1024 4096
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Consider a processor has virtual address 52 bits, the physical address is 32 bits and the page size is 16KB. Each individual table at any level of the page table occupies a single page of ... > <10,14,14,14> <4,14,14,14> <10,12,14,14>
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Compute the run time of a program which has 55.500.000 memory accesses, a TLB hit rate of 75%, and a page fault rate of 0,005. We consider the TLB ... the page table entry and updates the TLB. Which is the run time of the application??
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In a 32-bit machine we subdivide the virtual address into 4 segments as follows: 10-bit8-bit6-bit8 bitWe use a 3-level page table, such that ... 0xf0000000 and growing upwardWhat would be the change when the memory is nibble addressable ?
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A computer system with 2 level paging scheme in which regular memory access takes 300 nanoseconds and servicing a pagefault takes 500ns. An average instruction takes 200 ns ... 660 ns but made easy solution has 580 ns.Can any one check??
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In this problem I have a doubt that why effective access time is not taken as effective access time = 1 x 200 + p x (8 milliseconds)because even though ... page from disk to memory, plus, 200 nanoseconds for accessing all pages in memory
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Consider a simple paging system with the following characteristics: a page table size of 64 entries of 11 bits (including valid/invalid bit )each and a page size ... are there in physical address?(e) What is the size of physical address?
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Page making process from main memory to disk is calledInterruptionTerminationSwappingNone of the above
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In a paged memory, the page hit ratio is 0.35. The time required to access a page in secondary memory is 100 ns. The time required to access a page in primary ... ns. The average time required to access a page is100 ns68.0 ns68.5 ns78.5 ns
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Question related to: gate 2008_67Here is the question: https://gateoverflow.in/490/gate2008_67?show=61309#c61309"So, in the given question, a main memory page ... tables possible?Please correct my concept,at any level,where i went wrong.