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GO Classes 2023 | IIITH Mock Test 1 | Question: 29

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Consider a system with $\mathrm{N}$ bytes of physical RAM, and $\mathrm{M}$ bytes of virtual address space per process. Pages and frames are $\text{K}$ bytes in size. Every page table entry is $\mathrm{P}$ bytes in size, accounting for the extra flags required and such. What is the size of the page table of a process?

  1. $\mathrm{N} / \mathrm{K} \ast \mathrm{P}$
  2. $\mathrm{M} / \mathrm{N}\ast \mathrm{P}$
  3. $\mathrm{M} / \mathrm{K} \ast \mathrm{P}$
  4. $\mathrm{N} / \mathrm{P} \ast \mathrm{~K}$
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Number of virtual address blocks $=\mathrm{M} / \mathrm{K}$

So, number of page table entries $=\mathrm{M} / \mathrm{K}$ and page table entry size $=\text{P}$

So, Size of page table $=\mathrm{M} / \mathrm{K} \ast \mathrm{P}.$
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