Question

With segmentation, if there are 64 segments and maximum segment size is 512 words; the length of logical address is how many bits a) 12 b) 6 c) 15 d) 9

Answer 1

CPU always generates a logical address.

CPU generates a logical address consisting of two parts

$S$

$D$

 

  1.S=SEGEMENT NUMBER

   2.D=SEGEMENT OFFSET          

  Assuming Memory is word Addressable,

  Number of Segements=64

  S= Bits used to represent Segement Number=$\large \log 64{\color{Red} }$=$6$ bits

  D=Bits used to represent Offset

  Since Maximum segement size is 512 words

  D=$\large \log 512{\color{Red} }$=$9$ bits.

  Length of Logical address=S+D=$6$+$9$=$15$ BIts.

  Hope it helps. $:))$