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Effective access time= 0.35*10+(1-0.35)(10+100) = 3.5+0.65*110 = 75ns
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jatin khachane 1 asked Dec 15, 2018
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My approach: Given EMAT = 44 = (1-p)(m) + p(page fault service + m) . p = page fault ratePage fault service = (0.6) * 10 + (0.4)* (3) ==> 7.24 ... = (1-p)(1) + p(7.2)In page fault also we should consider Memory access time right ..??