Recent questions tagged simplification

226
views
1 answers
0 votes
Q.16 Simplify the Boolean expression.\[Y=A B+A(B+C)+B(B+C)\]Ans1. $Y=B+A C$2. $Y=A+B C$3. $Y=C+A B$ ... : 6306801082190Option 2 ID : 6306801082189Option 3 ID : 6306801082191Option 4 ID : 6306801082192Status : AnsweredChosen Option : 2
2.7k
views
1 answers
0 votes
Simplify the Following boolean function by means of the tabulation method.(a) P(A,B,C,D,E,F,G)=$\sum(20,28,52,60)$(b) P(A,B,C,D,E,F,G)= $\sum(20,28,38,39,52,60,102,103,127)$(C) P(A,B,C,D,E,F) = $\sum(6,9,13,18,19,25,27,29,41,45,57,61)$
4.9k
views
1 answers
2 votes
Implement the following boolean function F together with the don’t-care conditions d using no more than two NOR gates. Assume both normal and the compliment inputs are available.F(A,B,C,D) = $\sum(0,1,2,9,11) $d(A,B,C,D) = \sum(8,10,14,15)$
3.8k
views
1 answers
2 votes
A logic circuit implements the following Boolean function:F = A’C + AC’D’it is found that the circuit input combination A=C=1 can never occur. Find a simpler expression for F using the proper don't-care conditions.
545
views
0 answers
0 votes
Simplify the boolean function F together with the don't care conditions d in (1) sum of products and (2)product of sums.(A) $F(w,x,y,z) = \sum(0,1,2,3,7,8,10)$d(w,x,y,z) = \sum ... D) = \sum (3,4,13,15)$d(A,B,C,D) =\sum(1,2,5,6,8,10,12,14)$
517
views
0 answers
0 votes
Simplify the following boolean function F together with the don't care condition d; then express the simplified function in the sum of minterms.(a)$F(x,y,z)=\sum(0,1,2,4,5) $ ... ) = \sum(1,3,5,7,9,15)$d(A,B,C,D)= \sum(4,6,12,13)$
579
views
0 answers
0 votes
List the Eight degenerate 2 level forms and show that they reduce to the single operation. Explain how the degenerate two-level forms can be used to extend the number of inputs to a gate.
525
views
0 answers
0 votes
Implement the function F with the Following two level Forms: NAND-AND, AND-NOR, OR-NAND, AND NOR-OR.F(A,B,C,D) = $\sum(0,1,2,3,4,8,9,12)$
500
views
0 answers
0 votes
Find the eight different two-level gate circuit to implement F = xy’z + x’yz + w.
1.8k
views
0 answers
0 votes
Simplify the following functions and implement them with (15) two- level NOR gate circuits (16) three-level NOR gate circuits.F = wx’ + y’z’ + w’yz’F(w,x,y,z) = $\sum(5,6,9,10)$
661
views
0 answers
0 votes
Draw the NAND gate logic diagram that implements the complement of the following funcions:F(A,B,C,D) = $\sum ( 0,1,2,3,4,8,9,12)$
806
views
0 answers
1 votes
Simplify the following expressions and implement them with (12)two-level NAND gate circuits (17) three-level NAND gate circuits(a) AB’ + ABD + ABD’ + A’C’D + A’BC’(b) BD + BCD’ + AB’C’D’
585
views
0 answers
0 votes
Simplify the following boolean expressions into (1) Product of sums (2) sum of products.x’z’ + y’z’ + yz’ + xyAC’ + B’D + A’CD + ABCD(A’ + B’ + D’)(A + B’ + C’)(A’ + B + D’)(B + C’ + D’)
526
views
0 answers
0 votes
Simplify the following boolean functions in product of sums:F(w,x,y,z) = $\sum(0,2,5,6,7,8,10)$F(A,B,C,D) = $\prod(1,3,5,7,13,15)$F(x,y,z) = $\sum(2,3,6,7)$F(A,B,C,D) = $\prod(0,1,2,3,4,10,11)$
1.6k
views
0 answers
0 votes
Simplify the following boolean function using five variable maps.F(A,B,C,D,E) = $\sum (0,1,4,5,16,17,25,21,29)$F(A,B,C,D,E) = $\sum (0,2,3,4,5,6,7,11,15,16,18,19,23,27,31)$F= A’B’CE’ + A’B’C’D + B’D’E’ + B’CD’ + CDE’ + BDE’
451
views
0 answers
1 votes
Simplify the following boolean functions by first finding the essential prime implicants.F(w,x,y,z) = $\sum (0,2,4,5,6,7,8,10.13,15)$F(A,B,C,D) = $\sum (0,2,3,5,7,8,10,11,14,15)$F(A,B,C,D) = $\sum (1,3,4,5,10,11,12,13,14,15)$
701
views
0 answers
1 votes
Find the Minterms of the each of the following expression by first plotting each function in the map.xy + yz + xy’zC’D + ABC’ +ABD’ + A’B’Dwxy + x’z’ + w’xz
1.1k
views
0 answers
4 votes
Simplify the following boolean expressions using Four variable K-maps.w’z + xz + x’y + wx’zB’D + A’BC’ + AB’C + ABC’AB’C + B’C’D’ + BCD + ACD’ + A’B’C + A’BC’Dwxy + yz + xy’z + x’y
401
views
0 answers
0 votes
Simplify the following boolean functions using four variable K- mapsF(A,B,C,D) = $\sum (0,1,2,4,5,7,11,15)$F(w,x,y,z) = $\sum (1,4,5,6,12,14,15)$F(A,B,C,D) = $\sum (0,2,4,5,6,7,8,10,13,15)$F(w,x,y,z) = $\sum (2,3,10,11,12,13,14,15)$
664
views
0 answers
0 votes
Simplify the following boolean functions using four variable K- mapsF(A,B,C,D) = $\sum (4,6,7,15)$F(w,x,y,z) = $\sum (2,3,12,13,14,15)$F(A,B,C,D) = $\sum (3,7,11,13,14,15)$
536
views
0 answers
0 votes
Simplify the Following Boolean Expressions using three-variable k-map.xy + x’y’z’ + x’yz’x’y’ + yz + x’yz ’A’B + BC’ + B’C’
1.2k
views
0 answers
1 votes
Simplify the following Boolean functions using Three-Variable maps.F(x,y,z) = $\sum (0,1,5,7)$F(x,y,z) = $\sum (1,2,3,6,7)$F(x,y,z) = $\sum (3,5,6,7)$F(A,B,C) = $\sum (0,2,3,4,6)$
36.1k
views
2 answers
5 votes
Express the following function in the sum of minterms and The product of the maxterms.(a) F(A,B,C,D) = B’D + A’D + BD(b)F(x,y,z)=(xy + z)(xz + y)
3.4k
views
2 answers
1 votes
Find the complement of X + YZ; then show that F.F’=0 and F + F’ = 1
9.9k
views
1 answers
4 votes
Reduce the Following Boolean Expressions to the indicated numbers of the literalsA'C' + ABC +AC' to three literals(X'Y' + Z')' + Z + XY + WZ to three literalsA'B(D' + C'D) ... ) to one literals(A' + C)(A' + C')(A+ B + C'D) to four literals
1.8k
views
1 answers
2 votes
Simplify the Boolean expression to the minimum numbers of the literals. $ABC + A’B + ABC’$X’YZ + XZ$( X+ Y)’(X’ + Y’)$XY + X(WZ + WZ’)$(BC’ + A’D)(AB’ + CD’)$
7.8k
views
1 answers
2 votes
Simplify the following boolean Expressions to the minimum number of Literalsx’y’ + xy + x’y(x + y)(x + y’)x’y + xy’ + xy + x’y’x’ + xy + xz’ + xy’z’xy’ + y’z’ + x’z’
837
views
0 answers
0 votes
Consider the grammar G with Productions$S \rightarrow A|B,$A \rightarrow λ,$B \rightarrow aBb,$B \rightarrow b$.Construct a Grammar $\hat{G}$ by applying the algorithm in Theorem 6.3.
620
views
1 answers
0 votes
How to find log of the first n natural numbers?$T(n)= \log 1+ \log 2+ \log 3+\ldots + \log n$ // How to proceed from here?
3.0k
views
1 answers
1 votes
S -> ABA -> aBB | epsilonB -> bAA | epsilonWhat will be the CFG after removal of NULL productionMy doubt is in this grammer epsilon is also accepted So we ... What should be the answer of such problem if said to get rid of null productions?