Recent questions tagged effective-memory-access

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Q.1 What is diffrence between EMAT(effective) and AMAT(average mem access time)?Q.2 Suppose we have L1 cache ,L2cache and MM , and H1,M1, T1: hit/miss ratio, ... ration of L2. amd MM access time is t3. Then how to calculate EMAT and AMAT?
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Suppose the time taken to write in cache is tc and time to write in main memory is tm. If write back policy is used, only the main memory is written and time ... (time taken would be tm) or serially (time taken would be tc + tm)?
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In a system, with virtual memory the memory access time is 400 nanoseconds, if the page fault service time is double the memory access time, then what ... in GATE point of view if Numerical Type question is given without options .
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Compute the average access time for a machine with 80%cache hit ratio.The cache access time and memory access time are 20 ns and 200 ns .DOUBT:: While solving these type ... we need to follow case 1 or case 2 ?PS: Circle is a processor :P
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In Numerical answer type questions, when we have to consider simultaneous memory access and when we have to use hierarchical memory access model? How to know it?
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Suppose cache with hit ratio 'Ch' and access time 'Ct' is given and main memory with hit ratio 'Mh' and access time 'Mt' is given and a disk with access time 'Dt' is ... ) * ( Ct + Mt + Dt)If so, why the addition and is it implicit always ?
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Assume that a hypothetical system in which program execution gives 200 stall cycles per instruction on an average. There are 260 and 120 misses in L1 (Level1) and L2 ( ... per instruction]a. 300, 600b. 400, 800c. 160, 320d. 160, 340
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I got some doubt while solving previous year questions:-Since While calculating EMAT and question involves page fault service time,we use formulae:-p*s+(1-p)*m ,taken ... doubt we are not using 2m instead of m in case of NOT a page fault?
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What has to be the general and final formula for calculating the effective memory access time, taking in consideration the $\alpha$-level page table, TLB ... be so many formulae, each different from each other depending on the question.
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A computer has a cache, main memory and a hard disk used for virtual memory. If referenced word is in cache, 20 ns are required to access it. If it is in ... 1-cachehit) (Tcache + Memoryhit*TMemory +( 1- Memoryhit) (TMemory+Tsec. memory ) )
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A computer has a cache, main memory, and a disk used for virtual memory. If a referenced word is in the cache,Cpu access it from cache.. If it is in ... ,Main memory access time is 10 ns. Edit:- Disk accessed was mentioned twice.Updated it
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TLB hit rate=90%TLB access time=1nsMain memory access time=100nspage fault rate=20%Page fault service time=20 ms2 level paging is usedFind out the effective memory access ... know which answer is correct.If my idea is wrong why it is wrong?
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Suppose it takes $100$ ns to access a page table and $20$ ns to access associative memory with a $90$% hit rate, the average access time equals :$28$ $20$ $90$ $100$
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Considering hierarchical method,is my this equation correct?Assuming tlb access time as 0 nsEMAT = 300 [memory access time] + 0.2*(300*2)[2 level page table] + 0.2 * (500)Average instruction execution time = Emat + 200. = 720 ns.
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if i use hierarchical system then the equation : 50 = 10 + 0.3(p*400 + (1-p)*125)... is correct?
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Let the page fault service time be 10ms in a computer with average memory access time being 20ns. If one page fault is generated for every 10^6 memory ... explain in detail what is the difference among them, I found them as similar.
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Actually there is solution also but not able to take screen shot. My solution is :TA1 = 0.95*30+0.05*300TA2=0.95*30+0.05*270TA1-TA2=3nsAm I correct?
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Can anyone explains when to use this formulas?Average memory access time (AMAT)AMAT = Hit Time + Miss Rate * Miss PenalityOR• Effective Access Time:1. Hit Rate * Hit ... mem access time) + (1-H)(TLB access + PT access + mem access)]
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64 word cache and main memory is divided into 16 words block.The access time of cache is 10ns/word and for main memory is 50ns/word. The hit ratio for ... . 40% reference is for write operation. Avg access time if write through is used.