Recent questions tagged area

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In the given figure, $\text{PQRSTV}$ is a regular hexagon with each side of length $5\mathrm{~cm}.$ A circle is drawn with its centre at $ \mathrm{V}$ ... ) $\frac{25 \pi}{3}$ $\frac{20 \pi}{3}$ $6 \pi$ $7\pi$
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Two straight lines pass through the origin $(x_{0}, y_{0}) = (0, 0)$. One of them passes through the point $(x_{1}, y_{1}) = (1, 3)$ and the other passes through the ... $ on the $x$-axis?$0.5$1.0$1.5$2.0$
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In the following diagram, the point $\text{R}$ is the center of the circle. The lines $\text{PQ}$ and $\text{ZV}$ are tangential to the circle. The relation among the ... of $\text{PXWR}$ = Area of $\text{RUVZ}$ - Area of $\text{SPQT}$
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If $f\left ( x \right ) = 2 \:\ln \left ( \sqrt{e^{x}} \right )$, what is the area bounded by $f\left ( x \right )$ for the interval $\left [ 0,2 \right ]$ on the $x$ – axis?$\frac{1}{2}$1$2$4$
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Equal sized circular regions are shaded in a square sheet of paper of $1$ cm side length. Two cases, case $\text{M}$ and case $\text{N}$, are considered as shown in the figures below. ... $? $2 : 3$1 : 1$3 : 2$2 : 1$
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Four points $\text{P(0, 1), Q(0, – 3), R( – 2, – 1),}$ and $\text{S(2, – 1)}$ represent the vertices of a quadrilateral.What is the area enclosed by the quadrilateral?$4$4 \sqrt{2}$8$8 \sqrt{2}$
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A function $y(x)$ is defined in the interval $[0, 1]$ on the $x - $ ... $ on the $x - $ axis?$\frac{5}{6}$\frac{6}{5}$\frac{13}{6}$\frac{6}{13}$
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Consider a square sheet of side $1$ unit. The sheet is first folded along the main diagonal. This is followed by a fold along its line of symmetry. The resulting folded shape is again ... $\frac{1}{8}$\frac{1}{16}$\frac{1}{32}$
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In the above figure, $\textsf{O}$ is the center of the circle and, $\textsf{M}$ and $\textsf{N}$ lie on the circle. The area of the right triangle $\textsf{MON}$ ... the area of the circle in $\text{cm}^{2}?$2\pi$50\pi$75\pi$100\pi$
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In the figure shown above, each inside square is formed by joining the midpoints of the sides of the next larger square. The area of the smallest square (shaded) as shown, in $\text{cm}^{2}$ is:$12.50$6.25$3.125$1.5625$
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​​Corners are cut from an equilateral triangle to produce a regular convex hexagon as shown in the figure above.The ratio of the area of the regular convex hexagon to the area of the original equilateral triangle is$2:3$3:4$4:5$5:6$
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A circle with centre $\text{O}$ is shown in the figure. A rectangle $\text{PQRS}$ of maximum possible area is inscribed in the circle. If the radius of the circle is $a$, then the area ... $\pi a^{2}-3a^{2}$
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The figure below shows an annular ring with outer and inner as $b$ and $a$, respectively. The annular space has been painted in the form of blue colour circles touching the outer and inner ... )^{2}]$\pi [(b^{2}-a^{2})+n(b-a)^{2}]$
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If $A(t)$ is the area of the region bounded by the curve $y=e^{-\mid x \mid}$ and the portion of the $x$-axis between $-t$ and $t$, then $\underset{t \to \infty}{\lim} A(t)$ equals$0$1$2$4$
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The area under the curve $x^2+3x-4$ in the positive quadrant and bounded by the line $x=5$ is equal to$59 \frac{1}{6}$61 \frac{1}{3}$40 \frac{2}{3}$72$
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The volume of the solid, generated by revolving about the horizontal line $y=2$ the region bounded by $y^2 \leq 2x$, $x \leq 8$ and $y \geq 2$, is$2 \sqrt{2\pi}$28 \pi/3$84 \pi$none of the above
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The shaded region in the following diagram represents the relation$y \leq x$\mid y \mid \leq \mid x \mid$y \leq \mid x \mid$\mid y \mid \leq x$
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The shaded region in the following diagram represents the relation$y\:\leq\: x$\mid \:y\mid \:\leq\: \mid x\:\mid $y\:\leq\: \mid x\:\mid$\mid \:y\mid\: \leq\: x$
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The set $\{(x,y)\: :\: \mid x\mid+\mid y\mid\:\leq\:1\}$ is represented by the shaded region in
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Four tangents are drawn to the ellipse $\dfrac{x^{2}}{9}+\dfrac{y^{2}}{5}=1$ at the ends of its latera recta. The area of the quadrilateral so formed is$27$\frac{13}{2}$\frac{15}{4}$45$
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The area bounded by $y=x^{2}-4,y=0$ and $x=4$ is$\frac{64}{3}$6$\frac{16}{3}$\frac{32}{3}$
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The area of the shaded region in the following figure (all the arcs are circular) is$\pi$2 \pi$3 \pi$\frac{9}{8} \pi$
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The area (in square unit) of the portion enclosed by the curve $\sqrt{2x}+ \sqrt{2y} = 2 \sqrt{3}$ and the axes of reference is$2$4$6$8$
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The area of the region bounded by the curves $y=\sqrt x,$ $2y+3=x$ and $x$-axis in the first quadrant is$9$\frac{27}{4}$36$18$
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The area lying in the first quadrant and bounded by the circle $x^2+y^2=4$ and lines $x=0 \text{ and } x=1$ is given by$\frac{\pi}{3}+\frac{\sqrt{3}}{2}$\frac{\pi}{6}+ ... $\frac{\pi}{6}+\frac{\sqrt{3}}{2}$
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The area bounded by the curves $y^2 =x, y=x $ is given by$2/3$1/2$1/6$1/3$
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