Recent posts tagged study-resources

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I think there is a typing mistake by gate2015, it should be 5-4-6=-5 rather than 5-6-4=-5.
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in line [a] we have not specified anything like who is walking and then in line [c] we have used HIM.
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#include <stdio.h> void e(int); int main() { int a = 3; e(a); putchar('\n'); return 0; } void e(int n) { if (n > 0) { e(--n); printf("%d ", n); e(--n); } }I am not getting here that when e(0) is called how is the code executed ?
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Five stages:(IF), instruction decode and register fetch (ID/RF),instruction execution (EX),memory access (MEM), and register writeback (WB)P old design:with stage latencies ... $\dfrac{P}{Q}=\dfrac{3.08}{2}=1.54$
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thanku this thing was not know to me..
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R12(ABCD) and R3(BE); its lossy because B being common ,but it is not the key for R12(ABCD) and R3(BE)..!
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i made a calculation mistake here.. logy=limx&rarr;0 2 / ax+bx.(axloga+bxlogb)it should be-logy=limx&rarr;0 2 / ax+bx ( 1/2axloga+1/2bxlogb)logy=limx&rarr;0 ... log b)logy = 1/2 log ablog y= log&radic;aby=&radic;ab thanks again :) :)
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can we check isomorphism of graph in this way .??delete the maximun degree vertex in first graph and second graph again apply this argument to the resulting graph. ... very simple so that we can easily map one graph to another graph.??
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Take a single person A out of the 10 people. The remaining 9 people has to be either friends or enemy with A. Therefore acc to pigeon hole principle ... are either three mutual enemies or four mutual friends by assuming A has 5 enemies.
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this is one of the best solution for this type of question when by putting limit of x in given question it forms 1infinity form then we apply formula given belowsuch type of ... , according to above formula elim x->0 (1-x-1)*1/x =e-1
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