0 votes 0 votes The number of possible paranthesizations of a sequence of n matrices is O(n) $\theta$(n Ig n) $\Omega(2^n)$ None of the above Algorithms ugcnetcse-sep2013-paper3 algorithms dynamic-programming matrix-chain-ordering + – go_editor asked Jul 24, 2016 • recategorized Oct 19, 2018 by Pooja Khatri go_editor 1.4k views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes possible parenthesized of a sequence of n matrices is Ω($2^{n}$) altamash answered Aug 1, 2019 altamash comment Share Follow See 1 comment See all 1 1 comment reply kd..... commented Nov 28, 2019 reply Follow Share how??? 0 votes 0 votes Please log in or register to add a comment.