0 votes 0 votes Two fair 6-face diced are tossed independently. Let X be the random variable of the sum of two numbers on dices and let Y be the absolute difference of two numbers on dices. What is the value of P( X $\geq$ 2Y)? a) 22/36 b) 24/36 c) 26/36 c) 28/36 d) 32/36 Probability iit-madras written-test admissions probability random-variable + – harshrajhrj asked Apr 30 • recategorized Apr 30 by harshrajhrj harshrajhrj 293 views answer comment Share Follow See 1 comment See all 1 1 comment reply ꧁༒☬ĿọŗԀ 🆂🅷🅸🆅🅰☬༒꧂ commented May 4 i edited by ꧁༒☬ĿọŗԀ 🆂🅷🅸🆅🅰☬༒꧂ Jun 10 reply Follow Share bro all options correct ? i m getting 30/36 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes $X$ is R V Sum of two number of dices. And $Y$ R V be the difference of two number on dices. Only these Pairs are not satisfying the cases $(1,4), (4,1),(1,5),(5,1), (1,6), (6,1)$ $P(X>=2Y)$ = $fav$ $ cases$ $/$ $total$ $cases $ = $30/36$ ꧁༒☬ĿọŗԀ 🆂🅷🅸🆅🅰☬༒꧂ answered Jun 10 ꧁༒☬ĿọŗԀ 🆂🅷🅸🆅🅰☬༒꧂ comment Share Follow See all 0 reply Please log in or register to add a comment.