Not transitive because $4\text{R}6$ and $6\text{R}9$ But $4$ is not related to $9.$
$\text{R}$ is not reflexive since $\gcd(1,1)=1$ and $1\text{R}1$ is false.
$\text{R}$ is symmetric since if $x\text{R}y$ then $\gcd(x,y)>1$ and $\gcd(y,x) = \gcd(x,y)>1$ and therefore $y\text{R}x.$
$\text{R}$ is not transitive: $2\text{R}6$ and $6\text{R}3$ are both true but $2\text{R}3$ is false.
