0 votes 0 votes An operating system implements a single level paging. This system uses Translation Lookaside Buffer (TLB) and Physical Address Cache (PAC) as well. TLB has a hit ratio 90%. PAC has a miss ratio of 20%. Main memory access time, TLB access time and PAC access time are 100 ns, 20 ns and 40 ns respectively. Assuming that all the pages of the process are in main memory, the effective memory access time is ______ (ns). Operating System test-series operating-system memory-management effective-memory-access + – LRU asked Nov 3, 2021 LRU 939 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
Best answer 2 votes 2 votes Effective memory access time (or) EMAT = 90/100 [ 20 + (80/100)*40 (20/100) * (40 + 100)] + 10/100 [ 20 + 100 + (80/100)*40 + (20/100) * (40 + 100)] = 0.9 [ 20 + 32 + 28] 0.1 [ 120 + 32 + 28 ] = 0.9 [80] + 0.1 [ 180 ] = 72 + 18 = 90 ns Vishal_kumar98 answered Nov 3, 2021 • selected Nov 4, 2021 by LRU Vishal_kumar98 comment Share Follow See all 0 reply Please log in or register to add a comment.