EX OR operation can be seen as sum mod 2, that is divide the sum by 2 and see the remainder.
for example 1⊕1=2 mod 2=0,
1⊕0=1 mod 2=1,
0⊕0=0 mod 2=0,
0⊕1=1 mod 2=1
you can also check 1⊕1⊕1⊕1⊕1⊕1=6 mod 2=0
Given option (a) 1⊕0 will be 1 mod 2=1 true
option (b) 1⊕1⊕0 will be 2 mod 2=0 but in option it is given as 1 hence it is incorrect.
option (c) 1⊕1⊕1 will be 3 mod 2=1 true
option (d) 1⊕1=0 true
Hence Option (B) Is Incorrect.