0 votes 0 votes Let $L=$ {$a^nb^m:n\geq100,m\leq50$}. (a) Can you use the pumping lemma to show that L is regular? (b) Can you use the pumping lemma to show that L is not regular? Explain your answers. Theory of Computation peter-linz peter-linz-edition4 theory-of-computation regular-language pumping-lemma + – Naveen Kumar 3 asked Apr 12, 2019 Naveen Kumar 3 267 views answer comment Share Follow See 1 comment See all 1 1 comment reply prashant jha 1 commented Apr 13, 2019 reply Follow Share 1. Pumping lemma cannot be used to show that a language is regular , so here to prove whether the language is regular we cannot use pumping lemma. 2. Pumping lemma is a negative check , i.e it is mainly used to show that a language is not regular , so yes here we can use pumping lemma to disprove the regularity of the language . Here we already know that the language is a regular language , since a finite automata can be constructed for the language . The DFA will have 151 states. 0 votes 0 votes Please log in or register to add a comment.