2 votes 2 votes lw $R2,100($R5) sw $R2,200($R6)............ with out any bypass paths how many cycles does the sw instruction.. need to stall for? 5 stage pipeline CO and Architecture pipelining stall + – monty asked Nov 24, 2015 • retagged Jul 9, 2017 by Arjun monty 603 views answer comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes without bypass i.e. without operand forwarding IF ID EX PO WB IF - - - ID PO WB there will be 3 stalls srestha answered Nov 24, 2015 srestha comment Share Follow See all 4 Comments See all 4 4 Comments reply monty commented Nov 24, 2015 reply Follow Share R2,100(add R2, (R5)R2,200(R2,200(sub R2,(R6)............. with out any bypass paths how many cycles does the sw instruction.. need to stall for? 5 stage pipeline now.......... 0 votes 0 votes srestha commented Nov 24, 2015 reply Follow Share it is also indirect addressing . here also 3 stalls In the previous one given indirect addressing with address of memory location 100 and here memory location not given 0 votes 0 votes asu commented May 16, 2016 reply Follow Share why these 3 stall cycle ? 0 votes 0 votes jatinmittal199510 commented Sep 16, 2016 reply Follow Share I think there will be no stalls as both the instructions are independent. The first instruction uses the value of R5 whereas the second instruction is using the value of register R6. Whether it's operand forwarding or without forwarding, it will not take any stall cycles. 1 votes 1 votes Please log in or register to add a comment.
