2 votes 2 votes Say Client buffer is of 12000 Bytes and MSS is 1200 B and this info is sent to server and now server send the info in (SYN +ACK) segment as Server Buffer = 18000 B and MSS is 600 B Now in data transfer phase does both Client and Server will choose 600 Bytes data segments because both Client and server agree on minimum (MSS of Client, MSS of Server) = Min (1200, 600) = 600 Bytes? Or does the sever will send 1200 Bytes segments to C and C sends 600 B segments to server? Computer Networks computer-networks tcp ip-packet network + – iarnav asked Dec 16, 2018 iarnav 772 views answer comment Share Follow See 1 comment See all 1 1 comment reply darshansharma_ commented Nov 28, 2019 reply Follow Share What is its answer? 0 votes 0 votes Please log in or register to add a comment.
0 votes 0 votes According to me, the TCP window size is min (CnWD, RWnd). So firstly the size of window at both the sides will be 12000B. The MSS on both sides remain the same . rish1602 answered Jan 28, 2021 • edited Jul 11, 2021 by rish1602 rish1602 comment Share Follow See all 0 reply Please log in or register to add a comment.
0 votes 0 votes According to me, the TCP window size is min (CnWD, RWnd). So firstly the size of window at both the sides will be 12000B. The MSS on both sides remain the same . rish1602 answered May 2, 2021 • edited Jul 11, 2021 by rish1602 rish1602 comment Share Follow See all 0 reply Please log in or register to add a comment.
