Source of question - https://gateoverflow.in/1540/gate2013-29
Consider a hard disk with 16 recording surfaces (0−15) having 16384 cylinders (0−16383) and each cylinder contains 64 sectors (0−63). Data storage capacity in each sector is 512 bytes. Data are organized cylinder-wise and the addressing format is <cylinder no., surface no., sector no.> . A file of size 42797 KB is stored in the disk and the starting disk location of the file is <1200,9,40>. What is the cylinder number of the last sector of the file, if it is stored in a contiguous manner?
- 1281
- 1282
- 1283
- 1284
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I've seen all the answers answered there, but I'm not getting this question. The only part till I got is the last sector to store the file, but couldn't get the reverse engineering thing given in best answer.
Someone please simplify and explain this question
