Compiler Design - Parsing: Is LALR(1) made from the LR(0) or the LR(1) automaton?

Question

According to my understanding, we LALR is constructed by reducing LR(1) automaton states. So I think it should be LR(1)

However, we construct SLR(1) items from the LR(0) automaton, and we say with surety that number of states in SLR(...) is equal to number of states in LALR(...), how can this be?

Answer 1

LALR is constructed using CLR(1). by reducing the similar state but different look ahead

Comments

Yes..

and $\text{no. of states in LR(0)=SLR(1)=LALR(1)}\le CLR(1)$